2n^2-14n+12=0

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Solution for 2n^2-14n+12=0 equation: 



2n^2-14n+12=0

a = 2; b = -14; c = +12;
Δ = b2-4ac
Δ = -142-4·2·12
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$


$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-10}{2*2}=\frac{4}{4}
=1
$


$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+10}{2*2}=\frac{24}{4}
=6
$

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